Below we try to model some concepts of argumentation theory in B. The examples try to show that set theory can be used to model some aspects of argumentation theory quite naturally, and that ProB can solve and visualise some problems in argumentation theory. Alternative solutions are encoding arguments as normal logic programs and using answer set solvers for problem solving.
The following model was inspired by a talk given by Claudia Schulz.
The model below represents the labelling of the arguments as a total function from arguments to its status, which can either be in (the argument is accepted), out (the argument is rejected), or undec (the argument is undecided). The relation between the arguments is given in the binary attacks relation.
In case you are new to B, you probably need to know the following operators to understand the specification below (we als have a summary page about the B syntax):
MACHINE ArgumentationTotFun SETS ARGUMENTS={A,B,C,D,E}; STATUS = {in,out,undec} CONSTANTS attacks, label PROPERTIES attacks : ARGUMENTS <-> ARGUMENTS /* which argument attacks which other argument */ & label: ARGUMENTS --> {in,out,undec} & /* the labeling function */ // if an argument y is in any attacker must be out: !(x,y).(x|->y:attacks => (label(y)=in => label(x)=out)) & // if an argument x is in anything it attacks must be out: !(x,y).(x|->y:attacks => (label(x)=in => label(y)=out)) & //if an argument y is out it must be attacked by a valid argument: !(y).(y:ARGUMENTS => (label(y)=out => #x.(x|->y:attacks & label(x)=in))) & // if an argument y is undecided it must be attacked by an undecided argument: !(y).(y:ARGUMENTS => (label(y)=undec => #x.(x|->y:attacks & label(x)=undec))) & // here we model one particular argumentation graph // A = the sun will shine to day, B = we are in the UK, C = it is summer, D = there are only 10 days of sunshine per year, E = the BBC has forecast sun attacks = {B|->A, C|->B, D|->C, E |-> B, E|->D} END
Here is a screenshot of ProB Tcl/Tk after loading the model.
You can see that there is only a single solution (solving time 10 ms), as only a single SETUP_CONSTANTS line is available in the "Enabled Operations" pane. Double-click on SETUP_CONSTANTS and then INITIALISATION will give you the following result, where you can see the solution in the "State Properties" pane:
If you want to inspect the solution visually, you can select the "Current State as Graph" command in the "States" submenu of the "Visualize" menu:
This results in the following picture being displayed:
You can try and experiment with various attack graphs by editing the file. E.g., with
attacks = {B|->A, C|->B, D|->C, E |-> B, E|->D, D|->E}
you now get three possible labelling, the last one assigns undec to all arguments.
The following is a slightly more elegant encoding, where we represent the labelling as a partition of the arguments. This enables to use the relational image operator to express some constraints more compactly. This model is particularly well suited if you wish to use our Kodkod backend which translates the constraints to SAT. However, even the standard ProB solver can solve this instance in 10 ms (Kodkod requires 70 ms), so this would only be worthwhile for larger problem instances.
In case you are new to B, you probably need to know the following additional operators to understand the specification below (we als have a summary page about the B syntax):
MACHINE ArgumentationAsSets SETS ARGUMENTS={A,B,C,D,E} CONSTANTS attacks, in,out,undec PROPERTIES attacks : ARGUMENTS <-> ARGUMENTS /* which argument attacks which other argument */ & // we partition the arguments into three sets ARGUMENTS = in \/ out \/ undec & in /\ out = {} & in /\ undec = {} & out /\ undec = {} & // if an argument is in, any attacker must be out: attacks~[in] <: out & // if an argument is in, anything it attacks must be out: attacks[in] <: out & //if an argument y is out, it must be attacked by a valid argument: !y.(y:out => #x.(x|->y:attacks & x:in)) & // if an argument y is undecided, it must be attacked by an undecided argument: !y.(y:undec => #x.(x|->y:attacks & x:undec)) & // here we model one particular argumentation graph // A = the sun will shine to day, B = we are in the UK, C = it is summer, D = there are only 10 days of sunshine per year, E = the BBC has forecast sun attacks = {B|->A, C|->B, D|->C, E |-> B, E|->D} END
Instead of using ProB Tcl/Tk you can also encode this model in Rodin. Here we have split the model into two contexts. The first one encodes the general rules for labelling (we use Camille syntax):
context ArgumentsAsSets sets ARGUMENTS constants attacks in out undec axioms @axm1 attacks ∈ ARGUMENTS ↔ ARGUMENTS // which argument attacks which other argument @axm2 partition(ARGUMENTS,in,out,undec) // we partition the arguments into three sets @axm3 attacks∼[in] ⊆ out // if an argument is in, any attacker must be out @axm4 attacks[in] ⊆ out // if an argument is in, anything it attacks must be out @axm5 ∀y·(y∈out ⇒ ∃x·(x↦y∈attacks ∧ x∈in)) //if an argument y is out, it must be attacked by a valid argument @axm6 ∀y·(y∈undec ⇒ ∃x·(x↦y∈attacks ∧ x∈undec)) // if an argument y is undecided, it must be attacked by an undecided argument end
A second context then extends the above one, and encodes our particular problem instance:
context Arguments_Example extends ArgumentsAsSets constants A B C D E axioms @part partition(ARGUMENTS,{A},{B},{C},{D},{E}) @example attacks = {B↦A, C↦B, D↦C, E ↦ B, E↦D} /* A = the sun will shine to day, B = we are in the UK C = it is summer, D = there are only 10 days of sunshine per year, E = the BBC has forecast sun */ end
If you load this model with ProB for Rodin, you can see the solution in the State view: