Argumentation Theory: Difference between revisions

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you now get three possible labelling, the last one assigns <b>undec</b> to all arguments.
you now get three possible labelling, the last one assigns <b>undec</b> to all arguments.


[[File:ProB_Argumentation_Dot1.png|200px|center]][[File:ProB_Argumentation_Dot2.png|200px|center]][[File:ProB_Argumentation_Dot3.png|200px|center]]
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<tr>
<td>[[File:ProB_Argumentation_Dot1.png|200px|center]]</td>
<td>[[File:ProB_Argumentation_Dot2.png|200px|center]]</td>
<td>[[File:ProB_Argumentation_Dot3.png|200px|center]]</td>
</tr>
</table>


== A more elegant encoding ==
== A more elegant encoding ==

Revision as of 15:10, 20 January 2016

Below we try to model some concepts of argumentation theory in B. The examples try to show that set theory can be used to model some aspects of argumentation theory quite naturally, and that ProB can solve and visualise some problems in argumentation theory. Alternative solutions are encoding arguments as normal logic programs and using answer set solvers for problem solving.

The following model was inspired by a talk given by Claudia Schulze.

The model below represents the labelling of the arguments as a total function from arguments to its status, which can either be in (the argument is accepted), out (the argument is rejected), or undec (the argument is undecided). The relation between the arguments is given in the binary attacks relation.

In case you are new to B, you probably need to know the following operators to understand the specification below (we als have a summary page about the B syntax):

  • x : S specifies that x is an element of S
  • a|->b represents the pair (a,b); note that a relation and function in B is a set of pairs.
  • x|->y : R hence specifies that x is mapped to y in relation R
  • !x.(P => Q) denotes universal quantification over variable x
  • #x.(P & Q) denotes universal quantification over variable x
  • A <--> B denotes the set of relations from A to B
  • A --> B denotes the set of total functions from A to B
  • block comments are of the form /* ... */ and line comments start with // (be sure to use version 1.5.1 of ProB, e.g., from the Nightly download site as line comments were added recently to B)
MACHINE ArgumentationTotFun
SETS
 ARGUMENTS={A,B,C,D,E};
 STATUS = {in,out,undec}
CONSTANTS attacks, label
PROPERTIES
  attacks : ARGUMENTS <-> ARGUMENTS  /* which argument attacks which other argument */
  &
  label: ARGUMENTS --> {in,out,undec} & /* the labeling function */

  // if an argument y is in any attacker must be out:
  !(x,y).(x|->y:attacks => (label(y)=in => label(x)=out)) &
  // if an argument x is in anything it attacks must be out: 
  !(x,y).(x|->y:attacks => (label(x)=in => label(y)=out)) &
  //if an argument y is out it must be attacked by a valid argument:
  !(y).(y:ARGUMENTS => (label(y)=out => #x.(x|->y:attacks & label(x)=in))) & 
  // if an argument y is undecided it must be attacked by an undecided argument:
  !(y).(y:ARGUMENTS => (label(y)=undec => #x.(x|->y:attacks & label(x)=undec))) 
 &
  // here we model one particular argumentation graph
  // A = the sun will shine to day, B = we are in the UK, C = it is summer, D = there are only 10 days of sunshine per year, E = the BBC has forecast sun
  attacks = {B|->A, C|->B, D|->C, E |-> B, E|->D} 
END


Here is a screenshot of ProB Tcl/Tk after loading the model.

ProB Argumentation Screenshot1.png

You can see that there is only a single solution (solving time 10 ms), as only a single SETUP_CONSTANTS line is available in the "Enabled Operations" pane. Double-click on SETUP_CONSTANTS and then INITIALISATION will give you the following result, where you can see the solution in the "State Properties" pane:

ProB Argumentation Screenshot2.png


If you want to inspect the solution visually, you can select the "Current State as Graph" command in the "States" submenu of the "Visualize" menu:


ProB Argumentation VisCurStateAsGraph.png

This results in the following picture being displayed:


ProB Argumentation Dot.png

You can try and experiment with various attack graphs by editing the file. E.g., with

attacks = {B|->A, C|->B, D|->C, E |-> B, E|->D, D|->E} 

you now get three possible labelling, the last one assigns undec to all arguments.

ProB Argumentation Dot1.png
ProB Argumentation Dot2.png
ProB Argumentation Dot3.png

A more elegant encoding

The following is a slightly more elegant encoding, where we represent the labelling as a partition of the arguments. This enables to use the relational image operator to express some constraints more compactly. This model is particularly well suited if you wish to use our Kodkod backend which translates the constraints to SAT. However, even the standard ProB solver can solve this instance in 10 ms (Kodkod requires 70 ms), so this would only be worthwhile for larger problem instances.

In case you are new to B, you probably need to know the following additional operators to understand the specification below (we als have a summary page about the B syntax):

  • r~ is the inverse of a function or relation r
  • r[S] is the relational image of a relation r for a set of domain values S


MACHINE ArgumentationAsSets
SETS
 ARGUMENTS={A,B,C,D,E};
 STATUS = {in,out,undec}
CONSTANTS attacks, lin,lout,lundec
PROPERTIES
  attacks : ARGUMENTS <-> ARGUMENTS  /* which argument attacks which other argument */
  &
  // we partition the arguments into three sets
  ARGUMENTS = lin \/ lout \/ lundec &
  lin /\ lout = {} & lin /\ lundec = {} & lout /\ lundec = {} &
  
  // if an argument is in, any attacker must be out:
  attacks~[lin] <: lout &
  // if an argument is in, anything it attacks must be out: 
  attacks[lin] <: lout &
  //if an argument y is out, it must be attacked by a valid argument:
  !y.(y:lout => #x.(x|->y:attacks & x:lin)) & 
  // if an argument y is undecided, it must be attacked by an undecided argument:
  !y.(y:lundec => #x.(x|->y:attacks & x:lundec))

 &
  // here we model one particular argumentation graph
  // A = the sun will shine to day, B = we are in the UK, C = it is summer, D = there are only 10 days of sunshine per year, E = the BBC has forecast sun
  attacks = {B|->A, C|->B, D|->C, E |-> B, E|->D} 
END